| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
| 24750 ft⋅lb | |
| 18 ft⋅lb | |
| 4 ft⋅lb | |
| 36 ft⋅lb |
When it comes to force, mass and acceleration have what kind of relationship?
logarithmic |
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linear |
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exponential |
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inverse |
Newton's Second Law of Motion states that "The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object." This Law describes the linear relationship between mass and acceleration when it comes to force and leads to the formula F = ma or force equals mass multiplied by rate of acceleration.
Torque involves a perpendicular force applied to a lever arm that moves around a center of rotation. Increasing the length of the lever arm will do which of the following?
decrease applied force |
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increase applied force |
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increase torque |
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decrease torque |
Torque measures force applied during rotation: τ = rF. Torque (τ, the Greek letter tau) = the radius of the lever arm (r) multiplied by the force (F) applied. Radius is measured from the center of rotation or fulcrum to the point at which the perpendicular force is being applied. The resulting unit for torque is newton-meter (N-m) or foot-pound (ft-lb).
| 12.5 lbs. | |
| 3.13 lbs. | |
| 1.56 lbs. | |
| 9.38 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Rb, our missing value, and plugging in our variables yields:
Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{5 lbs. \times 5 ft.}{8 ft.} \) = \( \frac{25 ft⋅lb}{8 ft.} \) = 3.13 lbs.
| 2 | |
| 1 | |
| 0 | |
| 3 |
The mechanical advantage (MA) of a wedge is its length divided by its thickness:
MA = \( \frac{l}{t} \) = \( \frac{6 in.}{3 in.} \) = 2