| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.12 |
| Score | 0% | 62% |
Sam can do 50 ft. lb. of work in 2 minutes and 5 seconds. What would Sam have to do to increase his power output?
do the work in 3 minutes |
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do the work in 2 minutes |
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do 100 ft. lb. of work in 4 minutes 12 seconds |
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do 25 ft. lb. of work in 2 minutes 5 seconds |
Power is the rate of doing work or \(\frac{W}{t}\). To increase power, increase the work being done in the same amount of time or do the same amount of work in less time.
Two or more pulleys used together are called:
block and tackle |
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wheel and axle |
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gears |
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third-class lever |
Two or more pulleys used together constitute a block and tackle which, unlike a fixed pulley, does impart mechanical advantage as a function of the number of pulleys that make up the arrangement. So, for example, a block and tackle with three pulleys would have a mechanical advantage of three.
Which of the following is the formula for hydraulic pressure?
P = FA2 |
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P = F/A |
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P = F/A2 |
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P = FA |
Hydraulics is the transmission of force through the use of liquids. Liquids are especially suited for transferring force in complex machines because they compress very little and can occupy very small spaces. Hydraulic pressure is calculated by dividing force by the area over which it is applied: P = F/A where F is force in pounds, A is area in square inches, and the resulting pressure is in pounds per square inch (psi).
Specific gravity is a comparison of the density of an object with the density of:
oil |
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carbon |
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water |
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air |
Specific gravity is the ratio of the density of equal volumes of a substance and water and is measured by a hyrdometer.
| 11.25 lbs. | |
| 3.75 lbs. | |
| 33.75 lbs. | |
| 22.5 lbs. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for Rb, our missing value, and plugging in our variables yields:
Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{45 lbs. \times 1 ft.}{4 ft.} \) = \( \frac{45 ft⋅lb}{4 ft.} \) = 11.25 lbs.