| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.30 |
| Score | 0% | 66% |
| 150ft⋅lb | |
| 300 ft⋅lb | |
| 600ft⋅lb | |
| 0ft⋅lb |
| 5 | |
| 5.5 | |
| 2 | |
| 4.5 |
Mechanical advantage (MA) can be calculated knowing only the distance the effort (blue arrow) moves and the distance the resistance (green box) moves. The equation is:
MA = \( \frac{E_d}{R_d} \)
where Ed is the effort distance and Rd is the resistance distance. For this problem, the equation becomes:
MA = \( \frac{9 ft.}{1.8 ft.} \) = 5
You might be wondering how having an effort distance of 5 times the resistance distance is an advantage. Remember the principle of moments. For a lever in equilibrium the effort torque equals the resistance torque. Because torque is force x distance, if the effort distance is 5 times the resistance distance, the effort force must be \( \frac{1}{5} \) the resistance force. You're trading moving 5 times the distance for only having to use \( \frac{1}{5} \) the force.
| 8.71 lbs. | |
| 12 lbs. | |
| 32.16 lbs. | |
| 19 lbs. |
The mechanical advantage of a wheel and axle is the input radius divided by the output radius:
MA = \( \frac{r_i}{r_o} \)
In this case, the input radius (where the effort force is being applied) is 12 and the output radius (where the resistance is being applied) is 7 for a mechanical advantage of \( \frac{12}{7} \) = 1.71
MA = \( \frac{load}{effort} \) so effort = \( \frac{load}{MA} \) = \( \frac{55 lbs.}{1.71} \) = 32.16 lbs.
The steering wheel of a car is an example of which type of simple machine?
first-class lever |
|
fixed pulley |
|
wheel and axle |
|
block and tackle |
A wheel and axle uses two different diameter wheels mounted to a connecting axle. Force is applied to the larger wheel and large movements of this wheel result in small movements in the smaller wheel. Because a larger movement distance is being translated to a smaller distance, force is increased with a mechanical advantage equal to the ratio of the diameters of the wheels. An example of a wheel and axle is the steering wheel of a car.
Which class of lever is used to increase force on an object in the same direction as the force is applied?
first |
|
second |
|
third |
|
all of these |
A second-class lever is used to increase force on an object in the same direction as the force is applied. This lever requires a smaller force to lift a larger load but the force must be applied over a greater distance. The fulcrum is placed at one end of the lever and mechanical advantage increases as the object being lifted is moved closer to the fulcrum or the length of the lever is increased. An example of a second-class lever is a wheelbarrow.