ASVAB Mechanical Comprehension Practice Test 916574 Results

Your Results Global Average
Questions 5 5
Correct 0 3.10
Score 0% 62%

Review

1

Power is the rate at which:

62% Answer Correctly

work is done

friction is overcome

potential energy is converted into kinetic energy

input force is transferred to output force


Solution

Power is the rate at which work is done, P = w/t, or work per unit time. The watt (W) is the unit for power and is equal to 1 joule (or newton-meter) per second. Horsepower (hp) is another familiar unit of power used primarily for rating internal combustion engines. 1 hp equals 746 watts.


2

Which of the following surfaces would have the highest coefficient of friction?

77% Answer Correctly

ice

marble

concrete

steel


Solution

Coefficient of friction (μ) represents how much two materials resist sliding across each other.  Smooth surfaces like ice have low coefficients of friction while rough surfaces like concrete have high μ.


3

The mechanical advantage of a wheel and axle is equal to the:

61% Answer Correctly

ratio of the diameters of the wheels

difference in the lengths of the axles

length of the axle

difference in the diameters of the wheels


Solution

A wheel and axle uses two different diameter wheels mounted to a connecting axle. Force is applied to the larger wheel and large movements of this wheel result in small movements in the smaller wheel. Because a larger movement distance is being translated to a smaller distance, force is increased with a mechanical advantage equal to the ratio of the diameters of the wheels. An example of a wheel and axle is the steering wheel of a car.


4 If the green box weighs 65 lbs. and is 1 ft. from the fulcrum, how far from the fulcrum would a 30 lbs. force need to be applied to balance the lever?
58% Answer Correctly
4.33 ft.
0 ft.
65 ft.
2.17 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{65 lbs. \times 1 ft.}{30 lbs.} \) = \( \frac{65 ft⋅lb}{30 lbs.} \) = 2.17 ft.


5 A mass of air has a pressure of 15.0 psi and a volume of 75 ft.3. If the air is compressed to a new volume of 55 ft.3, what is the new pressure?
56% Answer Correctly
20.5 psi
10.2 psi
6.8 psi
25.5 psi

Solution

According to Boyle's Law, pressure and volume are inversely proportional:

\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)

In this problem, V2 = 55 ft.3, V1 = 75 ft.3 and P1 = 15.0 psi. Solving for P2:

P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{15.0 psi}{\frac{55 ft.^3}{75 ft.^3}} \) = 20.5 psi