ASVAB Mechanical Comprehension Practice Test 926884 Results

Your Results Global Average
Questions 5 5
Correct 0 3.28
Score 0% 66%

Review

1

The force required to initally get an object moving is __________ the force required to keep it moving. 

76% Answer Correctly

lower than

opposite

higher than

the same as


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


2

A screw is most like which of the following other simple machines?

50% Answer Correctly

wheel and axle

first-class lever

inclined plane

block and tackle


Solution

A screw is an inclined plane wrapped in ridges (threads) around a cylinder. The distance between these ridges defines the pitch of the screw and this distance is how far the screw advances when it is turned once. The mechanical advantage of a screw is its circumference divided by the pitch.


3

Which of these is the formula for force?

77% Answer Correctly

F = a/m

F = ma

F = m/a

F = am2


Solution

Newton's Second Law of Motion states that "The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object." This Law describes the linear relationship between mass and acceleration when it comes to force and leads to the formula F = ma or force equals mass multiplied by rate of acceleration.


4 If the green box weighs 70 lbs. and 75 lbs. of force is applied 9 ft. from the fulcrum at the blue arrow, how far from the fulcrum would the green box need to be placed to balance the lever?
55% Answer Correctly
9.64 ft.
2.41 ft.
0 ft.
38.57 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{75 lbs. \times 9 ft.}{70 lbs.} \) = \( \frac{675 ft⋅lb}{70 lbs.} \) = 9.64 ft.


5 A = 4 ft., the green box weighs 30 lbs., and the blue box weighs 80 lbs. What does distance B need to be for this lever to balance?
65% Answer Correctly
1.5 ft.
7 ft.
6 ft.
4.5 ft.

Solution
In order for this lever to balance, the torque acting on side A must equal the torque acting on side B. Torque is weight x distance from the fulcrum which means that the following must be true for the lever to balance:

fAdA = fBdB

For this problem, the equation becomes:

30 lbs. x 4 ft. = 80 lbs. x dB

dB = \( \frac{30 \times 4 ft⋅lb}{80 lbs.} \) = \( \frac{120 ft⋅lb}{80 lbs.} \) = 1.5 ft.