| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.18 |
| Score | 0% | 64% |
The work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle. This defines which of the following?
conservation of mechanical energy |
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Pascal's law |
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work-energy theorem |
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mechanical advantage |
The work-energy theorem states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle. Simply put, work imparts kinetic energy to the matter upon which the work is being done.
Two gears are connected and the larger gear drives the smaller gear. The speed of rotation will __________ and the torque will __________.
decrease, increase |
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increase, decrease |
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decrease, decrease |
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increase, increase |
Connected gears of different numbers of teeth are used together to change the rotational speed and torque of the input force. If the smaller gear drives the larger gear, the speed of rotation will be reduced and the torque will increase. If the larger gear drives the smaller gear, the speed of rotation will increase and the torque will be reduced.
Collinear forces:
act in a common plane |
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pass through a common point |
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act along the same line of action |
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are unrelated to each other |
Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.
Torque involves a perpendicular force applied to a lever arm that moves around a center of rotation. Increasing the length of the lever arm will do which of the following?
decrease applied force |
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decrease torque |
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increase torque |
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increase applied force |
Torque measures force applied during rotation: τ = rF. Torque (τ, the Greek letter tau) = the radius of the lever arm (r) multiplied by the force (F) applied. Radius is measured from the center of rotation or fulcrum to the point at which the perpendicular force is being applied. The resulting unit for torque is newton-meter (N-m) or foot-pound (ft-lb).
| 4 ft. | |
| 16 ft. | |
| 1 ft. | |
| 25 ft. |
Win = Wout
Feffort x deffort = Fresistance x dresistance
In this problem, the effort work is 400 ft⋅lb and the resistance force is 100 lbs. and we need to calculate the resistance distance:
Win = Fresistance x dresistance
400 ft⋅lb = 100 lbs. x dresistance
dresistance = \( \frac{400ft⋅lb}{100 lbs.} \) = 4 ft.