ASVAB Mechanical Comprehension Practice Test 966832 Results

Your Results Global Average
Questions 5 5
Correct 0 3.36
Score 0% 67%

Review

1

Which of the following is not a type of bridge?

74% Answer Correctly

cable

truss

block

arch


Solution

The six basic bridge forms are beam, truss, arch, cantilever, cable, and suspension.


2

Friction between two or more solid objects that are not moving relative to each other is called:

74% Answer Correctly

dynamic friction

static friction

kinetic friction

gravitational friction


Solution

Static friction is friction between two or more solid objects that are not moving relative to each other. An example is the friction that prevents a box on a sloped surface from sliding farther down the surface.


3

A watt is the unit for which of the following?

71% Answer Correctly

work

energy

power

mechanical advantage


Solution

Power is the rate at which work is done, P = w/t, or work per unit time. The watt (W) is the unit for power and is equal to 1 joule (or newton-meter) per second. Horsepower (hp) is another familiar unit of power used primarily for rating internal combustion engines. 1 hp equals 746 watts.


4

Concurrent forces:

55% Answer Correctly

pass through a common point

act in a common plane

act in a common dimension

act along the same line of action


Solution

Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.


5 If 70 lbs. of force is applied 7 ft. from the fulcrum at the blue arrow and the green box is 4 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
62% Answer Correctly
10 lbs.
61.25 lbs.
367.5 lbs.
122.5 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{70 lbs. \times 7 ft.}{4 ft.} \) = \( \frac{490 ft⋅lb}{4 ft.} \) = 122.5 lbs.