| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.01 |
| Score | 0% | 60% |
What is work?
The movement of an object by a force |
|
The potential for exertion |
|
Force per unit time |
|
Force per unit distance |
Work is accomplished when force is applied to an object: W = Fd where F is force in newtons (N) and d is distance in meters (m). Thus, the more force that must be applied to move an object, the more work is done and the farther an object is moved by exerting force, the more work is done. By definition, work is the displacement of an object resulting from applied force.
The mass of an object correlates to the size of the object but ultimately depends on:
the object's potential energy |
|
the object's weight |
|
gravity |
|
the object's density |
Mass is a measure of the amount of matter in an object. In general, larger objects have larger mass than smaller objects but mass ultimately depends on how compact (dense) a substance is.
What's the last gear in a gear train called?
idler gear |
|
driven gear |
|
output gear |
|
driver gear |
A gear train is two or more gears linked together. Gear trains are designed to increase or reduce the speed or torque outpout of a rotating system or change the direction of its output. The first gear in the chain is called the driver and the last gear in the chain the driven gear with the gears between them called idler gears.
What type of load acts on a relatively small area of a structure?
non-uniformly distributed load |
|
concentrated load |
|
dynamic load |
|
impact load |
A concentrated load acts on a relatively small area of a structure, a static uniformly distributed load doesn't create specific stress points or vary with time, a dynamic load varies with time or affects a structure that experiences a high degree of movement, an impact load is sudden and for a relatively short duration and a non-uniformly distributed load creates different stresses at different locations on a structure.
| 0 ft. | |
| 1.94 ft. | |
| 15.56 ft. | |
| 3.89 ft. |
fAdA = fBdB
For this problem, the equation becomes:
50 lbs. x 7 ft. = 90 lbs. x dB
dB = \( \frac{50 \times 7 ft⋅lb}{90 lbs.} \) = \( \frac{350 ft⋅lb}{90 lbs.} \) = 3.89 ft.