ASVAB Mechanical Comprehension Practice Test 991932 Results

Your Results Global Average
Questions 5 5
Correct 0 3.57
Score 0% 71%

Review

1 If you lift a 38 lbs. rock 33 ft. from the ground, how much work have you done?
70% Answer Correctly
627 ft⋅lb
1254 ft⋅lb
2508 ft⋅lb
1 ft⋅lb

Solution
Work is force times distance. In this case, the force is the weight of the rock so:
\( W = F \times d \)
\( W = 38 \times 33 \)
\( W = 1254 \)

2

A box is resting on a smooth floor. Static friction is present:

59% Answer Correctly

when an attempt is made to move the box

only if normal force is present

if the coefficient of friction is greater than one

at all times


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


3

Drag is a type of:

81% Answer Correctly

work

potential energy

kinetic energy

friction


Solution

Drag is friction that opposes movement through a fluid like liquid or air. The amount of drag depends on the shape and speed of the object with slower objects experiencing less drag than faster objects and more aerodynamic objects experiencing less drag than those with a large leading surface area.


4

On Earth, acceleration due to gravity (g) is approximately __________. 

81% Answer Correctly

1 m/s2

1 m/s

9.8 m/s2

6.67 x 10-11 m/s2


Solution

Newton's Law of Univeral Gravitation defines the general formula for the attraction of gravity between two objects:  \(\vec{F_{g}} = { Gm_{1}m_{2} \over r^2}\) . In the specific case of an object falling toward Earth, the acceleration due to gravity (g) is approximately 9.8 m/s2. 


5 If 55 lbs. of force is applied 6 ft. from the fulcrum at the blue arrow and the green box is 2 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
62% Answer Correctly
55 lbs.
330 lbs.
0 lbs.
165 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{55 lbs. \times 6 ft.}{2 ft.} \) = \( \frac{330 ft⋅lb}{2 ft.} \) = 165 lbs.