| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.57 |
| Score | 0% | 71% |
| 627 ft⋅lb | |
| 1254 ft⋅lb | |
| 2508 ft⋅lb | |
| 1 ft⋅lb |
A box is resting on a smooth floor. Static friction is present:
when an attempt is made to move the box |
|
only if normal force is present |
|
if the coefficient of friction is greater than one |
|
at all times |
For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).
Drag is a type of:
work |
|
potential energy |
|
kinetic energy |
|
friction |
Drag is friction that opposes movement through a fluid like liquid or air. The amount of drag depends on the shape and speed of the object with slower objects experiencing less drag than faster objects and more aerodynamic objects experiencing less drag than those with a large leading surface area.
On Earth, acceleration due to gravity (g) is approximately __________.
1 m/s2 |
|
1 m/s |
|
9.8 m/s2 |
|
6.67 x 10-11 m/s2 |
Newton's Law of Univeral Gravitation defines the general formula for the attraction of gravity between two objects: \(\vec{F_{g}} = { Gm_{1}m_{2} \over r^2}\) . In the specific case of an object falling toward Earth, the acceleration due to gravity (g) is approximately 9.8 m/s2.
| 55 lbs. | |
| 330 lbs. | |
| 0 lbs. | |
| 165 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{55 lbs. \times 6 ft.}{2 ft.} \) = \( \frac{330 ft⋅lb}{2 ft.} \) = 165 lbs.