ASVAB Mechanical Comprehension Practice Test 995611 Results

Your Results Global Average
Questions 5 5
Correct 0 3.06
Score 0% 61%

Review

1

Specific gravity is a comparison of the density of an object with the density of:

57% Answer Correctly

carbon

water

air

oil


Solution

Specific gravity is the ratio of the density of equal volumes of a substance and water and is measured by a hyrdometer.


2

A wedge is most similar to what other type of simple machine?

70% Answer Correctly

second-class lever

third-class lever

first-class lever

inclined plane


Solution

The wedge is a moving inclined plane that is used to lift, hold, or break apart an object. A wedge converts force applied to its blunt end into force perpendicular to its inclined surface. In contrast to a stationary plane where force is applied to the object being moved, with a wedge the object is stationary and the force is being applied to the plane. Examples of a wedge include knives and chisels.


3 The green box weighs 25 lbs. and a 60 lbs. weight is placed 3 ft. from the fulcrum at the blue arrow. How far from the fulcrum would the green box need to be placed to balance the lever?
57% Answer Correctly
0 ft.
21.6 ft.
75 ft.
7.2 ft.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{60 lbs. \times 3 ft.}{25 lbs.} \) = \( \frac{180 ft⋅lb}{25 lbs.} \) = 7.2 ft.


4

Coplanar forces:

61% Answer Correctly

act in a common plane

have opposite dimensions

pass through a common point

act along the same line of action


Solution

Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.


5 If a 65 lbs. weight is placed 7 ft. from the fulcrum at the blue arrow and the green box is 4 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
61% Answer Correctly
227.5 lbs.
455 lbs.
37.92 lbs.
113.75 lbs.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{65 lbs. \times 7 ft.}{4 ft.} \) = \( \frac{455 ft⋅lb}{4 ft.} \) = 113.75 lbs.