| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.06 |
| Score | 0% | 61% |
Specific gravity is a comparison of the density of an object with the density of:
carbon |
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water |
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air |
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oil |
Specific gravity is the ratio of the density of equal volumes of a substance and water and is measured by a hyrdometer.
A wedge is most similar to what other type of simple machine?
second-class lever |
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third-class lever |
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first-class lever |
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inclined plane |
The wedge is a moving inclined plane that is used to lift, hold, or break apart an object. A wedge converts force applied to its blunt end into force perpendicular to its inclined surface. In contrast to a stationary plane where force is applied to the object being moved, with a wedge the object is stationary and the force is being applied to the plane. Examples of a wedge include knives and chisels.
| 0 ft. | |
| 21.6 ft. | |
| 75 ft. | |
| 7.2 ft. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{60 lbs. \times 3 ft.}{25 lbs.} \) = \( \frac{180 ft⋅lb}{25 lbs.} \) = 7.2 ft.
Coplanar forces:
act in a common plane |
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have opposite dimensions |
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pass through a common point |
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act along the same line of action |
Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.
| 227.5 lbs. | |
| 455 lbs. | |
| 37.92 lbs. | |
| 113.75 lbs. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{65 lbs. \times 7 ft.}{4 ft.} \) = \( \frac{455 ft⋅lb}{4 ft.} \) = 113.75 lbs.