ASVAB Mechanical Comprehension Principles Practice Test 858770 Results

Your Results Global Average
Questions 5 5
Correct 0 2.83
Score 0% 57%

Review

1 A mass of air has a pressure of 12.0 psi and a volume of 60 ft.3. If the air is compressed to a new volume of 50 ft.3, what is the new pressure?
57% Answer Correctly
4.8 psi
21.6 psi
14.4 psi
16.4 psi
Solution

According to Boyle's Law, pressure and volume are inversely proportional:

\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)

In this problem, V2 = 50 ft.3, V1 = 60 ft.3 and P1 = 12.0 psi. Solving for P2:

P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{12.0 psi}{\frac{50 ft.^3}{60 ft.^3}} \) = 14.4 psi

2 A mass of air has a pressure of 12.0 psi and a volume of 60 ft.3. If the air is compressed to a new volume of 50 ft.3, what is the new pressure?
57% Answer Correctly
4.8 psi
21.6 psi
14.4 psi
16.4 psi
Solution

According to Boyle's Law, pressure and volume are inversely proportional:

\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)

In this problem, V2 = 50 ft.3, V1 = 60 ft.3 and P1 = 12.0 psi. Solving for P2:

P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{12.0 psi}{\frac{50 ft.^3}{60 ft.^3}} \) = 14.4 psi

3 A mass of air has a pressure of 12.0 psi and a volume of 60 ft.3. If the air is compressed to a new volume of 50 ft.3, what is the new pressure?
57% Answer Correctly
4.8 psi
21.6 psi
14.4 psi
16.4 psi
Solution

According to Boyle's Law, pressure and volume are inversely proportional:

\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)

In this problem, V2 = 50 ft.3, V1 = 60 ft.3 and P1 = 12.0 psi. Solving for P2:

P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{12.0 psi}{\frac{50 ft.^3}{60 ft.^3}} \) = 14.4 psi

4 A mass of air has a pressure of 12.0 psi and a volume of 60 ft.3. If the air is compressed to a new volume of 50 ft.3, what is the new pressure?
57% Answer Correctly
4.8 psi
21.6 psi
14.4 psi
16.4 psi
Solution

According to Boyle's Law, pressure and volume are inversely proportional:

\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)

In this problem, V2 = 50 ft.3, V1 = 60 ft.3 and P1 = 12.0 psi. Solving for P2:

P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{12.0 psi}{\frac{50 ft.^3}{60 ft.^3}} \) = 14.4 psi

5 A mass of air has a pressure of 12.0 psi and a volume of 60 ft.3. If the air is compressed to a new volume of 50 ft.3, what is the new pressure?
57% Answer Correctly
4.8 psi
21.6 psi
14.4 psi
16.4 psi
Solution

According to Boyle's Law, pressure and volume are inversely proportional:

\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)

In this problem, V2 = 50 ft.3, V1 = 60 ft.3 and P1 = 12.0 psi. Solving for P2:

P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{12.0 psi}{\frac{50 ft.^3}{60 ft.^3}} \) = 14.4 psi